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NEW QUESTION # 73
The first DROP operation is performed on PRODUCTS table using this command:
DROP TABLE products PURGE;
Then a FLASHBACK operation is performed using this command:
FLASHBACK TABLE products TO BEFORE DROP;
Which is true about the result of the FLASHBACK command?

• A. It is not possible to recover the table structure, data, or the related indexes.
• B. It recovers only the table structure.
• C. It recovers the table structure and data but not the related indexes.
• D. It recovers the table structure, data, and the indexes.

Answer: A

Explanation:
Explanation
References:
https://docs.oracle.com/cd/B19306_01/server.102/b14200/statements_9003.htm

NEW QUESTION # 74
Which two statements are true regarding a SAVEPOINT?

• A. Rolling back to a SAVEPOINT can undo a TRUNCATE statement.
• B. A SAVEPOINT does not issue a COMMIT
• C. Rolling back to a SAVEPOINT can undo a DELETE statement
• D. Only one SAVEPOINT may be issued in a transaction.
• E. Rolling back to a SAVEPOINT can undo a CREATE INDEX statement.

Answer: B,C

Explanation:
Regarding the use of SAVEPOINT in transactions:
* C. A SAVEPOINT does not issue a COMMIT: A SAVEPOINT in Oracle SQL is used to mark a point within a transaction. It does not commit the transaction; rather, it allows partial rollbacks to the point of the SAVEPOINT without affecting other uncommitted changes outside it.
* E. Rolling back to a SAVEPOINT can undo a DELETE statement: SAVEPOINT allows you to rollback DML changes like INSERT, UPDATE, and DELETE that occur after the SAVEPOINT was established, but before a COMMIT.
Incorrect options:
* A: CREATE INDEX is a DDL statement, and like most DDL statements, it implicitly commits the transaction, making it impossible to rollback using a SAVEPOINT.
* B: Multiple SAVEPOINTS can be defined within a single transaction, each with unique or reused names.
* D: TRUNCATE is a DDL statement that also implicitly commits the transaction; hence it cannot be rolled back to a SAVEPOINT.

NEW QUESTION # 75
Examine this statement which executes successfully:
CREATE view emp80 AS
SELECT
FROM employees
WHERE department_ id = 80
WITH CHECK OPTION;
Which statement will violate the CHECK constraint?

• A. SELECT
  FROM emp80
  WHERE department_ id = 90;
• B. UPDATE emp80
  SET department. 1d =80;
  WHERE department_ id =90;
• C. SELECT
  FROM emp80
  WHERE department. id = 80;
• D. DELETE FROM emp80
  WHERE department_ id = 90;

Answer: D

Explanation:
In Oracle SQL, the WITH CHECK OPTION clause in a CREATE VIEW statement ensures that all data manipulation statements performed through the view must conform to the view's defining query.
* Option A: DELETE FROM emp80 WHERE department_id = 90;
* This will violate the CHECK constraint because the WHERE clause condition does not meet the view's restriction (department_id = 80). This statement attempts to delete rows that the view is not supposed to have access to (since it should only include rows where department_id is 80).
Options B, C, and D do not violate the CHECK constraint because:
* Option B: A SELECT statement does not modify data, so it does not violate the CHECK OPTION.
* Option C: Selecting rows with department_id = 80 is consistent with the view's definition.
* Option D: There is a syntax error, but assuming it meant to set department_id to 80 where it is currently 90, it still would not violate the CHECK constraint because the CHECK OPTION on a view does not prevent updates that do not change the rows to fall outside the view's filter. However, since department_id is supposed to be 80 as per the view definition, this update operation doesn't make logical sense, as there should be no rows with department_id = 90 to update.

NEW QUESTION # 76
View the Exhibit and examine the details of the PRODUCT_INFORMATION table.

You have the requirement to display PRODUCT_NAME and LIST_PRICE from the table where the CATEGORYJD column has values 12 or 13, and the SUPPLIER_ID column has the value 102088. You executed the following SQL statement:
SELECT product_name, list_price
FROM product_information
WHERE (category_id = 12 AND category_id = 13) AND supplier_id = 102088; Which statement is true regarding the execution of the query?

• A. It would not execute because the entire WHERE clause condition is not enclosed within the parentheses.
• B. It would not execute because the same column has been used in both sides of the AND logical operator to form the condition.
• C. It would execute and the output would display the desired result.
• D. It would execute but the output would return no rows.

Answer: D

NEW QUESTION # 77
View the Exhibit and examine the structure of the ORDER_ITEMS table. (Choose the best answer.)

You must select the ORDER_ID of the order that has the highest total value among all the orders in the ORDER_ITEMS table.
Which query would produce the desired result?

• A. SELECT order_idFROM order_itemsGROUP BY order_idHAVING SUM(unit_price*quantity) = (SELECT MAX (SUM(unit_price*quantity))FROM order_items GROUP BY order_id);
• B. SELECT order_idFROM order_itemsWHERE(unit_price*quantity) = (SELECT MAX (SUM(unit_price*quantity)FROM order_items) GROUP BY order_id);
• C. SELECT order_idFROM order_itemsWHERE (unit_price*quantity) = (SELECT MAX(unit_price*quantity)FROM order_itemsGROUP BY order_id)
• D. SELECT order_idFROM order_itemsWHERE(unit_price*quantity)
  MAX(unit_price*quantity)GROUP BY order_id);

Answer: A

NEW QUESTION # 78
You execute this query:
SELECT TO CHAR (NEXT_DAY(LAST_DAY(SYSDATE),'MON' ),' dd"Monday for" fmMonth rrr') FROM DUAL; What is the result?

• A. It executes successfully but does not return any result.
• B. It returns the date for the last Monday of the current month.
• C. It returns the date for the first Monday of the next month.
• D. It generates an error.

Answer: C

NEW QUESTION # 79
In the PROMOTIONS table, the PROMO_ BEGIN_DATE column is of data type and the default date format is DD-MON-RR Which two statements are true about expressions using PROMO_ BEGIN_DATE in a query?

• A. PROMO_ BEGIN_DATE - SYSDATE will return an error
• B. PROMO_ BEGIN_DATE - SYSDATE will return a number
• C. TONUMBER (PROMO BEGIN_DATE) - 5 will return a number
• D. PROMO_ BEGIN_DATE - 5 will return a date
• E. TODATE(PROMO BEGIN_DATE *5) will return a date

Answer: B,D

Explanation:
In Oracle SQL, when you subtract a number from a date, the result is a date. When you subtract one date from another, the result is the number of days between the two dates.
* B: PROMO_BEGIN_DATE - 5 will subtract 5 days from the PROMO_BEGIN_DATE, resulting in a new date that is 5 days earlier than PROMO_BEGIN_DATE.
* C: PROMO_BEGIN_DATE - SYSDATE will return the number of days between the PROMO_BEGIN_DATE and the current date (SYSDATE).
The incorrect options are:
* A: TONUMBER(PROMO_BEGIN_DATE) - 5 will not return a number because
PROMO_BEGIN_DATE is a date, and TONUMBER is not a valid function to convert dates to numbers in Oracle.
* D: PROMO_BEGIN_DATE - SYSDATE will not return an error; it will return the number of days between the two dates as explained above.
* E: TODATE(PROMO_BEGIN_DATE * 5) will not return a date because PROMO_BEGIN_DATE
* 5 is not a valid operation in Oracle SQL as you cannot multiply a date by a number, and TODATE is not a valid function. The correct function name is TO_DATE.
References:
* Oracle Documentation on Date Arithmetic: Database SQL Language Reference - Datetime Functions

NEW QUESTION # 80
You execute this command:
ALTER TABLE employees SET UNUSED (department_id);
Which two are true?

• A. A query can display data from the DEPARTMENT_ID column.
• B. The storage space occupied by the DEPARTMENT_ID column is released only after a COMMIT is issued.
• C. A new column with the name DEPARTMENT_ID can be added to the EMPLOYEES table.
• D. The DEPARTMENT_ID column is set to null for all tows in the table
• E. The DEPARTMENT_ID column can be recovered from the recycle bin
• F. No updates can be made to the data in the DEPARTMENT_ID column.

Answer: C,F

Explanation:
D). True, after setting the DEPARTMENT_ID column to UNUSED, you can add a new column with the name DEPARTMENT_ID to the EMPLOYEES table. The UNUSED clause does not delete the column, it only marks it as no longer being used.E. True, once a column is marked as UNUSED, you cannot make updates to it. It becomes inaccessible for DML operations.
A, B, C, and F are not correct because: A. Once a column is set to UNUSED, it is not available for queries. B.
The storage space is not immediately released after issuing a COMMIT; instead, the actual removal and space reclamation happen when you subsequently issue the DROP UNUSED COLUMNS operation. C. The DEPARTMENT_ID column is not set to null; instead, it's marked as UNUSED, which means it is no longer available for use. F. UNUSED columns are not placed into the recycle bin; they are just marked for deletion, and space can be reclaimed with the DROP UNUSED COLUMNS command.
References:
* Oracle documentation on ALTER TABLE: Oracle Database SQL Language Reference
* Understanding ALTER TABLE SET UNUSED: Oracle Database Administrator's Guide

NEW QUESTION # 81
Which statement is true about TRUNCATE and DELETE?

• A. You can never DELETE rows from a table if foreign key constraints will be violated.
• B. For large tables TRUNCATE is faster than DELETE.
• C. For tables with multiple indexes and triggers DELETE is faster than TRUNCATE.
• D. You can never TRUNCATE a table if foreign key constraints will be violated.

Answer: B

NEW QUESTION # 82
The CUSTOMERStable has a CUST_LAST_NAMEcolumn of data type VARCHAR2.
The table has two rows whose CUST_LAST_NAMEvalues are Anderson and Ausson.
Which query produces output for CUST_LAST_NAMEcontaining Oder for the first row and Aus for the second?

• A. customers;
  SELECT INITCAP (REPLACE(TRIM('son' FROM cust_last_name), 'An', 'O')) FROM
• B. SELECT REPLACE (TRIM(TRAILING 'son' FROM cust_last_name), 'An', 'O') FROM
• C. customers;
  SELECT REPLACE (SUBSTR(cust_last_name, -3), 'An', 'O') FROM customers;
• D. SELECT REPLACE (REPLACE(cust_last_name, 'son', ''), 'An', 'O') FROM customers;

Answer: D

NEW QUESTION # 83
Which three statements are true about an ORDER BY clause?

• A. An ORDR BY clause will always precede a HAVI NG clause if both are used in the same top-level
• B. An ORDER BY clause can perform a linguistic sort
• C. An ORDER BY clause always sorts NULL values last.
• D. An ORDER BY clause can perform a binary sort
• E. By default an ORDERBY clause sorts rows in ascending order

Answer: B,D,E

NEW QUESTION # 84
You execute this query:
SELECT TO CHAR (NEXT_DAY(LAST_DAY(SYSDATE),'MON' ),' dd"Monday for" fmMonth rrr') FROM DUAL; What is the result?

• A. It executes successfully but does not return any result.
• B. It returns the date for the last Monday of the current month.
• C. It returns the date for the first Monday of the next month.
• D. It generates an error.

Answer: C

Explanation:
The query uses TO_CHAR and NEXT_DAY functions to format and determine dates:
* B. It returns the date for the first Monday of the next month: The function NEXT_DAY(LAST_DAY(SYSDATE), 'MON') finds the next Monday after the last day of the current month, effectively giving the first Monday of the next month. The TO_CHAR formatting is used to return this in a readable format.

NEW QUESTION # 85
Examine the description or the CUSTOMERS table:

For Customers whose income level has a value, you want to display the first name and due amount as 5% of their credit limit. Customers whose due amount is null should not be displayed.
Which query should be used?

• A. SELECT cust_first_name, cust_credit_limit * .05 AS DUE_AMONT FROM customers WHERE cust_income_level IS NOT NULL AND due_amount IS NOT NULL;
• B. SELECT cust_first_name, cust_credit_limit * .05 AS DUE_AMONT FROM customers WHERE cust_income_level <> NULL AND due_amount <> NULL;
• C. SELECT cust_first_name, cust_credit_limit * .05 AS DUE_AMONT FROM customers WHERE cust_income_level IS NOT NULL AND cust_credit_limit IS NOT NULL;
• D. SELECT cust_first_name, cust_credit_limit * .05 AS DUE_AMONT FROM customers WHERE cust_income_level != NULL AND due_amount != NULL;
• E. SELECT cust_first_name, cust_credit_limit * .05 AS DUE_AMOUNT FROM customers WHERE cust_income_level != NULL AND cust_credit_level != NULL;

Answer: C

NEW QUESTION # 86
Which two statements are true regarding operators used with subqueries (Choose two.)

• A. =ANYand =ALLoperators have the same functionality.
• B. The NOT INoperator is equivalent to IS NULL.
• C. The INoperator cannot be used in single-row subqueries.
• D. The <ANYoperator means less than the maximum.
• E. The NOToperator can be used with IN, ANYand ALLoperators.

Answer: D,E

NEW QUESTION # 87
Which two are true?

• A. INSTR finds the offset within a character string, starting from position 0.
• B. INSTR finds the offset within a string of a single character only.
• C. FLOOR returns the largest integer less than or equal to a specified number.
• D. CONCAT joins two character strings together.
• E. CONCAT joins two or more character strings together.
• F. FLOOR returns the largest positive integer less than or equal to a specified number.

Answer: C,E

Explanation:
The CONCAT function and FLOOR function in Oracle SQL have specific behaviors:
A . CONCAT function joins two or more character strings into one string, making this statement true.
B . FLOOR function returns the largest integer that is less than or equal to the specified number, making this statement true.
C . While CONCAT can join two strings together, this statement is incomplete as it can join more than two.
D . INSTR can find the offset of a substring within a string, not just a single character.
E . INSTR starts searching the string from position 1 in Oracle SQL, not position 0.
F . FLOOR does return the largest integer less than or equal to the specified number, but it can be any integer, not just positive ones.
Reference:
Oracle Database SQL Language Reference, 12c Release 1 (12.1): "Single-Row Functions"

NEW QUESTION # 88
View the Exhibit and examine the details of the PRODUCT_INFORMATION table.
You have the requirement to display PRODUCT_NAME and LIST_PRICE from the table where the CATEGORYJD column has values 12 or 13, and the SUPPLIER_ID column has the value 102088. You executed the following SQL statement:
SELECT product_name, list_price
FROM product_information
WHERE (category_id = 12 AND category_id = 13) AND supplier_id = 102088; Which statement is true regarding the execution of the query?

• A. It would execute but would return no rows.
• B. It would not execute because the entire WHERE clause is not enclosed within parentheses.
• C. It would not execute because the same column has been used twice with the AND logical operator.
• D. It would execute and return the desired.

Answer: A

NEW QUESTION # 89
Examine this SQL statement:

Which two are true?

• A. The subquery is executed before the DELETEstatement is executed.
• B. All existing rows in the EMPLOYEEStable are deleted.
• C. The subquery is executed for every row in the EMPLOYEEStable.
• D. The subquery is not a correlated subquery.
• E. The DELETE statement executes successfully even if the subquery selects multiple rows.

Answer: A,C

NEW QUESTION # 90
Which three queries execute successfully?

• A. SELECT SYSDATE - DATE '2019-01-01' - 1 FROM DUAL;
• B. SELECT (SYSDATE-DATE '2019-01-01') / 1 FROM DUAL;
• C. SELECT 1 - SYSDATE- DATE '2019-01-01' FROM DUAL;
• D. SELECT SYSDATE / DATE '2019-01-01' - 1 FROM DUAL
• E. SELECT 1 / SYSDATE - DATE '2019-01-01' FROM DUAL;
• F. SELECT SYSDATE - 1 - DATE'2019-01-01' EROM DUAL;

Answer: A,B,F

Explanation:
In Oracle SQL, date arithmetic can be performed directly, subtracting one date from another to get the number of days between them:
* Option A:
* SELECT (SYSDATE - DATE '2019-01-01') / 1 FROM DUAL; This query successfully calculates the difference between the current date and a specific date.
* Option D:
* SELECT SYSDATE - DATE '2019-01-01' - 1 FROM DUAL; This query subtracts a specific date from the current date and then subtracts 1 more day, which will execute successfully.
* Option F:
* SELECT SYSDATE - 1 - DATE '2019-01-01' FROM DUAL; Similar to D, this will successfully compute the date difference minus one day.
Options B, C, and E are incorrect because:
* Option B and Option C: You cannot divide by a date or divide a date by a number.
* Option E: You cannot subtract a date from a number.

NEW QUESTION # 91
Which two are true about dropping columns from a table?

• A. A column drop is implicitly committed.
• B. A column that is referenced by another column in any other table cannot be dropped.
• C. A column can be removed only if it contains no data.
• D. Multiple columns can be dropped simultaneously using the ALTER TABLE command.
• E. A column must be set as unused before it is dropped from a table.
• F. A primary key column cannot be dropped.

Answer: A,B,D

NEW QUESTION # 92
You must display details of all users whose username contains the string 'ch_'.
Which query generates the required output? (Choose the best answer.)

• A. SELECT *FROM usersWHERE user_name LIKE '%ch_%'ESCAPE'%';
• B. SELECT *FROM usersWHERE user_name LIKE '%ch_';
• C. SELECT *FROM usersWHERE user_name LIKE '%ch\_%' ESCAPE '\';
• D. SELECT *FROM usersWHERE user_name LIKE 'ch\_%' ESCAPE '_';

Answer: A

NEW QUESTION # 93
View the Exhibit and examine the structure of the SALES and PRODUCTS tables. (Choose two.)

In the SALES table, PROD_ID is the foreign key referencing PROD_ID in the PRODUCTS table. You must list each product ID and the number of times it has been sold.
Examine this query which is missing a JOIN operator:

Which two JOIN operations can be used to obtain the required output? (Choose two.)

• A. RIGHT OUTER JOIN
• B. FULL OUTER JOIN
• C. JOIN
• D. LEFT OUTER JOIN

Answer: B,D

NEW QUESTION # 94
......

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